1+cos(6x)=2sin^2(3x)

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Solution for 1+cos(6x)=2sin^2(3x) equation: 


Simplifying
1 + cos(6x) = 2sin2(3x)

Remove parenthesis around (6x)
1 + cos * 6x = 2sin2(3x)

Reorder the terms for easier multiplication:
1 + 6cos * x = 2sin2(3x)

Multiply cos * x
1 + 6cosx = 2sin2(3x)

Remove parenthesis around (3x)
1 + 6cosx = 2in2s * 3x

Reorder the terms for easier multiplication:
1 + 6cosx = 2 * 3in2s * x

Multiply 2 * 3
1 + 6cosx = 6in2s * x

Multiply in2s * x
1 + 6cosx = 6in2sx

Solving
1 + 6cosx = 6in2sx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 6cosx = -1 + 6in2sx

Combine like terms: 1 + -1 = 0
0 + 6cosx = -1 + 6in2sx
6cosx = -1 + 6in2sx

Divide each side by '6osx'.
c = -0.1666666667o-1s-1x-1 + in2o-1

Simplifying
c = -0.1666666667o-1s-1x-1 + in2o-1

Reorder the terms:
c = in2o-1 + -0.1666666667o-1s-1x-1

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